Cracking Coding Interview - 4.1 Route Between Nodes

Route Between Nodes: Given a directed graph, design an algorithm to find out whether there is a route between two nodes.

Hints:#127

解法1

采用广度优先的算法来做,广度优先的话可以找到最短路径:

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public class Graph {
  private Node[] nodes;
}
public class Node {
  private Node[] children;
}

public boolean hasRoute(Node start, Node dest) {
  Queue<Node> nodes = new Queue<>();
  start.marked = true;
  nodes.enqueue(start);
  while (!nodes.isEmpty()) {
    Node node = nodes.dequeue();
    if (node == dest) {
      return true;
    }
		for (Node child : node.children) {
      if (!child.marked) {
        if (child == dest) {
          return true;
        }
        chid.marked = true;
        nodes.enqueue(child);
      }
    }    
  }
  return false;
}

解法2

虽然可以用深度优先的方法来做,但是这个得碰运气:

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public boolean hasRoute(Node start, Node dest) {
  if (start.visited) {
    return false;
  }
  start.visited = true;
  if (start == dest) {
    return true;
  }
  for (Node n : start.children) {
    if (hasRoute(n, dest)) {
      return true;
    }
  }
  return false;
}

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